Base | Representation |
---|---|
bin | 11010010000110110… |
… | …01110110100100011 |
3 | 1100101122122012211112 |
4 | 31020123032310203 |
5 | 212334100000120 |
6 | 10251043533535 |
7 | 1006261010552 |
oct | 151033166443 |
9 | 40348565745 |
10 | 14100000035 |
11 | 5a8609a7a0 |
12 | 289608a2ab |
13 | 14392526b4 |
14 | 97a8a7d99 |
15 | 577cd7bc5 |
hex | 3486ced23 |
14100000035 has 32 divisors (see below), whose sum is σ = 19530616320. Its totient is φ = 9664358400.
The previous prime is 14100000023. The next prime is 14100000037. The reversal of 14100000035 is 53000000141.
14100000035 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 14100000035 - 212 = 14099995939 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14099999965 and 14100000019.
It is not an unprimeable number, because it can be changed into a prime (14100000037) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 166730 + ... + 236640.
It is an arithmetic number, because the mean of its divisors is an integer number (610331760).
Almost surely, 214100000035 is an apocalyptic number.
14100000035 is a deficient number, since it is larger than the sum of its proper divisors (5430616285).
14100000035 is a wasteful number, since it uses less digits than its factorization.
14100000035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 70139.
The product of its (nonzero) digits is 60, while the sum is 14.
Adding to 14100000035 its reverse (53000000141), we get a palindrome (67100000176).
The spelling of 14100000035 in words is "fourteen billion, one hundred million, thirty-five", and thus it is an aban number.
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