14100041 has 2 divisors, whose sum is σ = 14100042. Its totient is φ = 14100040.

The previous prime is 14099993. The next prime is 14100043. The reversal of 14100041 is 14000141.

14100041 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 14100025 + 16 = 3755^2 + 4^2 .

It is an emirp because it is prime and its reverse (14000141) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14100041 is a prime.

It is a super-2 number, since 2×14100041² = 397622312403362, which contains 22 as substring.

Together with 14100043, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 14099995 and 14100031.

It is not a weakly prime, because it can be changed into another prime (14100043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7050020 + 7050021.

It is an arithmetic number, because the mean of its divisors is an integer number (7050021).

Almost surely, 2^14100041 is an apocalyptic number.

It is an amenable number.

14100041 is a deficient number, since it is larger than the sum of its proper divisors (1).

14100041 is an equidigital number, since it uses as much as digits as its factorization.

14100041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 16, while the sum is 11.

The square root of 14100041 is about 3755.0021304921. The cubic root of 14100041 is about 241.5869430779.

Subtracting from 14100041 its product of nonzero digits (16), we obtain a square (14100025 = 3755²).

Adding to 14100041 its reverse (14000141), we get a palindrome (28100182).

The spelling of 14100041 in words is "fourteen million, one hundred thousand, forty-one".