1410011141412 has 12 divisors (see below), whose sum is σ = 3290025996656. Its totient is φ = 470003713800.

The previous prime is 1410011141401. The next prime is 1410011141417. The reversal of 1410011141412 is 2141411100141.

It is a tau number, because it is divible by the number of its divisors (12).

It is a super-2 number, since 2×1410011141412² (a number of 25 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (1410011141417) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 58750464214 + ... + 58750464237.

Almost surely, 2^{1410011141412} is an apocalyptic number.

1410011141412 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

1410011141412 is an abundant number, since it is smaller than the sum of its proper divisors (1880014855244).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1410011141412 is a wasteful number, since it uses less digits than its factorization.

1410011141412 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 117500928458 (or 117500928456 counting only the distinct ones).

The product of its (nonzero) digits is 128, while the sum is 21.

Adding to 1410011141412 its reverse (2141411100141), we get a palindrome (3551422241553).

The spelling of 1410011141412 in words is "one trillion, four hundred ten billion, eleven million, one hundred forty-one thousand, four hundred twelve".