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141003251245 = 536319776471
BaseRepresentation
bin1000001101010001110…
…0101101111000101101
3111110221202111022201201
42003110130231320231
54302233313014440
6144435341005501
713121122601023
oct2032434557055
9443852438651
10141003251245
11548877286aa
12233b1853891
13103b1699c9c
146b78984713
153a03d4619a
hex20d472de2d

141003251245 has 8 divisors (see below), whose sum is σ = 169208778240. Its totient is φ = 112799349840.

The previous prime is 141003251239. The next prime is 141003251261. The reversal of 141003251245 is 542152300141.

141003251245 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a de Polignac number, because none of the positive numbers 2k-141003251245 is a prime.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 206641 + ... + 569830.

It is an arithmetic number, because the mean of its divisors is an integer number (21151097280).

Almost surely, 2141003251245 is an apocalyptic number.

It is an amenable number.

141003251245 is a deficient number, since it is larger than the sum of its proper divisors (28205526995).

141003251245 is an equidigital number, since it uses as much as digits as its factorization.

141003251245 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 812795.

The product of its (nonzero) digits is 4800, while the sum is 28.

Adding to 141003251245 its reverse (542152300141), we get a palindrome (683155551386).

The spelling of 141003251245 in words is "one hundred forty-one billion, three million, two hundred fifty-one thousand, two hundred forty-five".

Divisors: 1 5 36319 181595 776471 3882355 28200650249 141003251245