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14100473113 is a prime number
BaseRepresentation
bin11010010000111010…
…00010010100011001
31100101200112020202221
431020131002110121
5212334210114423
610251102024041
71006265021026
oct151035022431
940350466687
1014100473113
115a86393171
122896278021
131439389b1c
1497a98c54d
15577d7ce5d
hex348742519

14100473113 has 2 divisors, whose sum is σ = 14100473114. Its totient is φ = 14100473112.

The previous prime is 14100473111. The next prime is 14100473129. The reversal of 14100473113 is 31137400141.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7486229529 + 6614243584 = 86523^2 + 81328^2 .

It is a cyclic number.

It is not a de Polignac number, because 14100473113 - 21 = 14100473111 is a prime.

Together with 14100473111, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (14100473111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7050236556 + 7050236557.

It is an arithmetic number, because the mean of its divisors is an integer number (7050236557).

Almost surely, 214100473113 is an apocalyptic number.

It is an amenable number.

14100473113 is a deficient number, since it is larger than the sum of its proper divisors (1).

14100473113 is an equidigital number, since it uses as much as digits as its factorization.

14100473113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1008, while the sum is 25.

Adding to 14100473113 its reverse (31137400141), we get a palindrome (45237873254).

The spelling of 14100473113 in words is "fourteen billion, one hundred million, four hundred seventy-three thousand, one hundred thirteen".