Base | Representation |
---|---|
bin | 11010010000111010… |
… | …00010010100011001 |
3 | 1100101200112020202221 |
4 | 31020131002110121 |
5 | 212334210114423 |
6 | 10251102024041 |
7 | 1006265021026 |
oct | 151035022431 |
9 | 40350466687 |
10 | 14100473113 |
11 | 5a86393171 |
12 | 2896278021 |
13 | 1439389b1c |
14 | 97a98c54d |
15 | 577d7ce5d |
hex | 348742519 |
14100473113 has 2 divisors, whose sum is σ = 14100473114. Its totient is φ = 14100473112.
The previous prime is 14100473111. The next prime is 14100473129. The reversal of 14100473113 is 31137400141.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 7486229529 + 6614243584 = 86523^2 + 81328^2 .
It is a cyclic number.
It is not a de Polignac number, because 14100473113 - 21 = 14100473111 is a prime.
Together with 14100473111, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (14100473111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7050236556 + 7050236557.
It is an arithmetic number, because the mean of its divisors is an integer number (7050236557).
Almost surely, 214100473113 is an apocalyptic number.
It is an amenable number.
14100473113 is a deficient number, since it is larger than the sum of its proper divisors (1).
14100473113 is an equidigital number, since it uses as much as digits as its factorization.
14100473113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1008, while the sum is 25.
Adding to 14100473113 its reverse (31137400141), we get a palindrome (45237873254).
The spelling of 14100473113 in words is "fourteen billion, one hundred million, four hundred seventy-three thousand, one hundred thirteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •