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14101000541 is a prime number
BaseRepresentation
bin11010010000111110…
…00011000101011101
31100101201112001021022
431020133003011131
5212334324004131
610251121213525
71006302345515
oct151037030535
940351461238
1014101000541
115a86713461
1228964912a5
131439512c04
1497aa88845
15577e3437b
hex3487c315d

14101000541 has 2 divisors, whose sum is σ = 14101000542. Its totient is φ = 14101000540.

The previous prime is 14101000453. The next prime is 14101000619. The reversal of 14101000541 is 14500010141.

14101000541 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13368215641 + 732784900 = 115621^2 + 27070^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14101000541 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14101060541) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7050500270 + 7050500271.

It is an arithmetic number, because the mean of its divisors is an integer number (7050500271).

Almost surely, 214101000541 is an apocalyptic number.

It is an amenable number.

14101000541 is a deficient number, since it is larger than the sum of its proper divisors (1).

14101000541 is an equidigital number, since it uses as much as digits as its factorization.

14101000541 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 80, while the sum is 17.

Adding to 14101000541 its reverse (14500010141), we get a palindrome (28601010682).

The spelling of 14101000541 in words is "fourteen billion, one hundred one million, five hundred forty-one", and thus it is an aban number.