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14102000311 = 72014571473
BaseRepresentation
bin11010010001000101…
…10111001010110111
31100101210101211200211
431020202313022313
5212340103002221
610251154450251
71006314011350
oct151042671267
940353354624
1014102000311
115a87236613
122896893987
1314397a2ca9
1497ac68d27
155780806e1
hex3488b72b7

14102000311 has 4 divisors (see below), whose sum is σ = 16116571792. Its totient is φ = 12087428832.

The previous prime is 14102000303. The next prime is 14102000329. The reversal of 14102000311 is 11300020141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14102000311 - 23 = 14102000303 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14102000291 and 14102000300.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14102000111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1007285730 + ... + 1007285743.

It is an arithmetic number, because the mean of its divisors is an integer number (4029142948).

Almost surely, 214102000311 is an apocalyptic number.

14102000311 is a deficient number, since it is larger than the sum of its proper divisors (2014571481).

14102000311 is an equidigital number, since it uses as much as digits as its factorization.

14102000311 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2014571480.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 14102000311 its reverse (11300020141), we get a palindrome (25402020452).

The spelling of 14102000311 in words is "fourteen billion, one hundred two million, three hundred eleven", and thus it is an aban number.

Divisors: 1 7 2014571473 14102000311