14102049495 has 8 divisors (see below), whose sum is σ = 22563279216. Its totient is φ = 7521093056.

The previous prime is 14102049473. The next prime is 14102049497. The reversal of 14102049495 is 59494020141.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 14102049495 - 2⁵ = 14102049463 is a prime.

It is a super-3 number, since 3×14102049495³ (a number of 31 digits) contains 333 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14102049497) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 470068302 + ... + 470068331.

It is an arithmetic number, because the mean of its divisors is an integer number (2820409902).

Almost surely, 2^14102049495 is an apocalyptic number.

14102049495 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

14102049495 is a deficient number, since it is larger than the sum of its proper divisors (8461229721).

14102049495 is an equidigital number, since it uses as much as digits as its factorization.

14102049495 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 940136641.

The product of its (nonzero) digits is 51840, while the sum is 39.

The spelling of 14102049495 in words is "fourteen billion, one hundred two million, forty-nine thousand, four hundred ninety-five".