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14102132404397 is a prime number
BaseRepresentation
bin1100110100110110100010…
…0101111011000010101101
31211221011001212001122220212
43031031220211323002231
53322022131343420042
645554232530552205
72653562662434362
oct315155045730255
954834055048825
1014102132404397
114547754111774
1216b9107738665
137b3a96488a2b
1436a7927b2469
15196c67451482
hexcd36897b0ad

14102132404397 has 2 divisors, whose sum is σ = 14102132404398. Its totient is φ = 14102132404396.

The previous prime is 14102132404357. The next prime is 14102132404433. The reversal of 14102132404397 is 79340423120141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8359332345001 + 5742800059396 = 2891251^2 + 2396414^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14102132404397 is a prime.

It is a super-2 number, since 2×141021324043972 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14102132404307) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7051066202198 + 7051066202199.

It is an arithmetic number, because the mean of its divisors is an integer number (7051066202199).

Almost surely, 214102132404397 is an apocalyptic number.

It is an amenable number.

14102132404397 is a deficient number, since it is larger than the sum of its proper divisors (1).

14102132404397 is an equidigital number, since it uses as much as digits as its factorization.

14102132404397 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 145152, while the sum is 41.

The spelling of 14102132404397 in words is "fourteen trillion, one hundred two billion, one hundred thirty-two million, four hundred four thousand, three hundred ninety-seven".