14102561241311 has 2 divisors, whose sum is σ = 14102561241312. Its totient is φ = 14102561241310.

The previous prime is 14102561241163. The next prime is 14102561241323. The reversal of 14102561241311 is 11314216520141.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14102561241311 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14102561241341) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7051280620655 + 7051280620656.

It is an arithmetic number, because the mean of its divisors is an integer number (7051280620656).

Almost surely, 2^{14102561241311} is an apocalyptic number.

14102561241311 is a deficient number, since it is larger than the sum of its proper divisors (1).

14102561241311 is an equidigital number, since it uses as much as digits as its factorization.

14102561241311 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5760, while the sum is 32.

Adding to 14102561241311 its reverse (11314216520141), we get a palindrome (25416777761452).

The spelling of 14102561241311 in words is "fourteen trillion, one hundred two billion, five hundred sixty-one million, two hundred forty-one thousand, three hundred eleven".