Base | Representation |
---|---|
bin | 11010010001001101… |
… | …10000101010101111 |
3 | 1100101212022202112121 |
4 | 31020212300222233 |
5 | 212340333203010 |
6 | 10251232413411 |
7 | 1006325465650 |
oct | 151046605257 |
9 | 40355282477 |
10 | 14103022255 |
11 | 5a878743a3 |
12 | 28970a7267 |
13 | 1439a701aa |
14 | 97b053527 |
15 | 5781d33da |
hex | 3489b0aaf |
14103022255 has 16 divisors (see below), whose sum is σ = 19343900160. Its totient is φ = 9669337632.
The previous prime is 14103022247. The next prime is 14103022259. The reversal of 14103022255 is 55222030141.
14103022255 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 14103022255 - 23 = 14103022247 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14103022259) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 286572 + ... + 332158.
It is an arithmetic number, because the mean of its divisors is an integer number (1208993760).
Almost surely, 214103022255 is an apocalyptic number.
14103022255 is a deficient number, since it is larger than the sum of its proper divisors (5240877905).
14103022255 is an equidigital number, since it uses as much as digits as its factorization.
14103022255 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 54438.
The product of its (nonzero) digits is 2400, while the sum is 25.
Adding to 14103022255 its reverse (55222030141), we get a palindrome (69325052396).
The spelling of 14103022255 in words is "fourteen billion, one hundred three million, twenty-two thousand, two hundred fifty-five".
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