14103051551 has 4 divisors (see below), whose sum is σ = 14296244112. Its totient is φ = 13909858992.

The previous prime is 14103051541. The next prime is 14103051553. The reversal of 14103051551 is 15515030141.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 15515030141 = 13 ⋅1193463857.

It is a cyclic number.

It is not a de Polignac number, because 14103051551 - 2¹⁰ = 14103050527 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 14103051551.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14103051553) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 96596171 + ... + 96596316.

It is an arithmetic number, because the mean of its divisors is an integer number (3574061028).

Almost surely, 2^14103051551 is an apocalyptic number.

14103051551 is a deficient number, since it is larger than the sum of its proper divisors (193192561).

14103051551 is an equidigital number, since it uses as much as digits as its factorization.

14103051551 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 193192560.

The product of its (nonzero) digits is 1500, while the sum is 26.

Adding to 14103051551 its reverse (15515030141), we get a palindrome (29618081692).

The spelling of 14103051551 in words is "fourteen billion, one hundred three million, fifty-one thousand, five hundred fifty-one".