1410312131477 has 2 divisors, whose sum is σ = 1410312131478. Its totient is φ = 1410312131476.

The previous prime is 1410312131467. The next prime is 1410312131479. The reversal of 1410312131477 is 7741312130141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1220879144356 + 189432987121 = 1104934^2 + 435239^2 .

It is a cyclic number.

It is not a de Polignac number, because 1410312131477 - 2¹⁰ = 1410312130453 is a prime.

Together with 1410312131479, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1410312131479) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 705156065738 + 705156065739.

It is an arithmetic number, because the mean of its divisors is an integer number (705156065739).

Almost surely, 2^{1410312131477} is an apocalyptic number.

It is an amenable number.

1410312131477 is a deficient number, since it is larger than the sum of its proper divisors (1).

1410312131477 is an equidigital number, since it uses as much as digits as its factorization.

1410312131477 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 14112, while the sum is 35.

The spelling of 1410312131477 in words is "one trillion, four hundred ten billion, three hundred twelve million, one hundred thirty-one thousand, four hundred seventy-seven".