141040503110231 has 2 divisors, whose sum is σ = 141040503110232. Its totient is φ = 141040503110230.

The previous prime is 141040503110179. The next prime is 141040503110233. The reversal of 141040503110231 is 132011305040141.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-141040503110231 is a prime.

It is a super-2 number, since 2×141040503110231² (a number of 29 digits) contains 22 as substring.

Together with 141040503110233, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 141040503110231.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (141040503110233) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70520251555115 + 70520251555116.

It is an arithmetic number, because the mean of its divisors is an integer number (70520251555116).

Almost surely, 2^{141040503110231} is an apocalyptic number.

141040503110231 is a deficient number, since it is larger than the sum of its proper divisors (1).

141040503110231 is an equidigital number, since it uses as much as digits as its factorization.

141040503110231 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1440, while the sum is 26.

Adding to 141040503110231 its reverse (132011305040141), we get a palindrome (273051808150372).

The spelling of 141040503110231 in words is "one hundred forty-one trillion, forty billion, five hundred three million, one hundred ten thousand, two hundred thirty-one".