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14104134041 is a prime number
BaseRepresentation
bin11010010001010110…
…00000000110011001
31100101221102020121212
431020223000012121
5212341124242131
610251312312505
71006341106214
oct151053000631
940357366555
1014104134041
115a88463728
122897542735
13143a06c25a
1497b26277b
15578352a2b
hex348ac0199

14104134041 has 2 divisors, whose sum is σ = 14104134042. Its totient is φ = 14104134040.

The previous prime is 14104134001. The next prime is 14104134047. The reversal of 14104134041 is 14043140141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9544508416 + 4559625625 = 97696^2 + 67525^2 .

It is a cyclic number.

It is not a de Polignac number, because 14104134041 - 230 = 13030392217 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14104133998 and 14104134016.

It is not a weakly prime, because it can be changed into another prime (14104134047) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7052067020 + 7052067021.

It is an arithmetic number, because the mean of its divisors is an integer number (7052067021).

Almost surely, 214104134041 is an apocalyptic number.

It is an amenable number.

14104134041 is a deficient number, since it is larger than the sum of its proper divisors (1).

14104134041 is an equidigital number, since it uses as much as digits as its factorization.

14104134041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 14104134041 its reverse (14043140141), we get a palindrome (28147274182).

The spelling of 14104134041 in words is "fourteen billion, one hundred four million, one hundred thirty-four thousand, forty-one".