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141043130111 = 1310849471547
BaseRepresentation
bin1000001101011011010…
…0110101111011111111
3111111001112112101020202
42003112310311323333
54302324020130421
6144443323434115
713122115552652
oct2032664657377
9444045471222
10141043130111
11548a8196244
122340308593b
13103b9a20650
146b7dda5899
153a075c210b
hex20d6d35eff

141043130111 has 4 divisors (see below), whose sum is σ = 151892601672. Its totient is φ = 130193658552.

The previous prime is 141043130101. The next prime is 141043130147. The reversal of 141043130111 is 111031340141.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 111031340141 = 359309279499.

It is a cyclic number.

It is not a de Polignac number, because 141043130111 - 218 = 141042867967 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (141043130101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5424735761 + ... + 5424735786.

It is an arithmetic number, because the mean of its divisors is an integer number (37973150418).

Almost surely, 2141043130111 is an apocalyptic number.

141043130111 is a deficient number, since it is larger than the sum of its proper divisors (10849471561).

141043130111 is a wasteful number, since it uses less digits than its factorization.

141043130111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10849471560.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 141043130111 its reverse (111031340141), we get a palindrome (252074470252).

The spelling of 141043130111 in words is "one hundred forty-one billion, forty-three million, one hundred thirty thousand, one hundred eleven".

Divisors: 1 13 10849471547 141043130111