1410440244133 has 2 divisors, whose sum is σ = 1410440244134. Its totient is φ = 1410440244132.

The previous prime is 1410440244131. The next prime is 1410440244149. The reversal of 1410440244133 is 3314420440141.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1174149950724 + 236290293409 = 1083582^2 + 486097^2 .

It is an emirp because it is prime and its reverse (3314420440141) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1410440244133 - 2¹ = 1410440244131 is a prime.

Together with 1410440244131, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 1410440244095 and 1410440244104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1410440244131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 705220122066 + 705220122067.

It is an arithmetic number, because the mean of its divisors is an integer number (705220122067).

Almost surely, 2^{1410440244133} is an apocalyptic number.

It is an amenable number.

1410440244133 is a deficient number, since it is larger than the sum of its proper divisors (1).

1410440244133 is an equidigital number, since it uses as much as digits as its factorization.

1410440244133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18432, while the sum is 31.

Adding to 1410440244133 its reverse (3314420440141), we get a palindrome (4724860684274).

The spelling of 1410440244133 in words is "one trillion, four hundred ten billion, four hundred forty million, two hundred forty-four thousand, one hundred thirty-three".