Base | Representation |
---|---|
bin | 1100110101010011111000… |
… | …1101101001111100000100 |
3 | 1211221220101221122210000100 |
4 | 3031110332031221330010 |
5 | 3322134300400200104 |
6 | 50002014423444100 |
7 | 2654262143305656 |
oct | 315247615517404 |
9 | 54856357583010 |
10 | 14110011334404 |
11 | 4550027607477 |
12 | 16ba7462b6630 |
13 | 7b47508bbbab |
14 | 36acdcd626d6 |
15 | 197078ed4139 |
hex | cd53e369f04 |
14110011334404 has 72 divisors (see below), whose sum is σ = 36064912851968. Its totient is φ = 4651102814400.
The previous prime is 14110011334343. The next prime is 14110011334409. The reversal of 14110011334404 is 40443311001141.
14110011334404 is a `hidden beast` number, since 1 + 4 + 1 + 100 + 113 + 3 + 440 + 4 = 666.
It is not an unprimeable number, because it can be changed into a prime (14110011334409) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 3622747 + ... + 6429954.
Almost surely, 214110011334404 is an apocalyptic number.
It is an amenable number.
14110011334404 is an abundant number, since it is smaller than the sum of its proper divisors (21954901517564).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14110011334404 is a wasteful number, since it uses less digits than its factorization.
14110011334404 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10053145 (or 10053140 counting only the distinct ones).
The product of its (nonzero) digits is 2304, while the sum is 27.
Adding to 14110011334404 its reverse (40443311001141), we get a palindrome (54553322335545).
The spelling of 14110011334404 in words is "fourteen trillion, one hundred ten billion, eleven million, three hundred thirty-four thousand, four hundred four".
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