14110011340125 has 32 divisors (see below), whose sum is σ = 23486483879040. Its totient is φ = 7522959571200.

The previous prime is 14110011340097. The next prime is 14110011340141. The reversal of 14110011340125 is 52104311001141.

It is not a de Polignac number, because 14110011340125 - 2¹⁹ = 14110010815837 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14110011340095 and 14110011340104.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 4761820 + ... + 7134069.

It is an arithmetic number, because the mean of its divisors is an integer number (733952621220).

Almost surely, 2^{14110011340125} is an apocalyptic number.

14110011340125 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

It is an amenable number.

14110011340125 is a deficient number, since it is larger than the sum of its proper divisors (9376472538915).

14110011340125 is a wasteful number, since it uses less digits than its factorization.

14110011340125 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11899070 (or 11899060 counting only the distinct ones).

The product of its (nonzero) digits is 480, while the sum is 24.

Adding to 14110011340125 its reverse (52104311001141), we get a palindrome (66214322341266).

The spelling of 14110011340125 in words is "fourteen trillion, one hundred ten billion, eleven million, three hundred forty thousand, one hundred twenty-five".