Base | Representation |
---|---|
bin | 1100110101010011111101… |
… | …1110000011011000000000 |
3 | 1211221220110102022112110010 |
4 | 3031110333132003120000 |
5 | 3322134321244110422 |
6 | 50002020455304520 |
7 | 2654262520405122 |
oct | 315247736033000 |
9 | 54856412275403 |
10 | 14110032410112 |
11 | 45500384a1a11 |
12 | 16ba75137b140 |
13 | 7b475508ab22 |
14 | 36ad01a8b212 |
15 | 19707ac98b0c |
hex | cd53f783600 |
14110032410112 has 80 divisors (see below), whose sum is σ = 38886215520240. Its totient is φ = 4541159841792.
The previous prime is 14110032410107. The next prime is 14110032410183. The reversal of 14110032410112 is 21101423001141.
It is a super-2 number, since 2×141100324101122 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 158338543 + ... + 158427630.
It is an arithmetic number, because the mean of its divisors is an integer number (486077694003).
Almost surely, 214110032410112 is an apocalyptic number.
14110032410112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
14110032410112 is an abundant number, since it is smaller than the sum of its proper divisors (24776183110128).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14110032410112 is an equidigital number, since it uses as much as digits as its factorization.
14110032410112 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 316766223 (or 316766207 counting only the distinct ones).
The product of its (nonzero) digits is 192, while the sum is 21.
Adding to 14110032410112 its reverse (21101423001141), we get a palindrome (35211455411253).
The spelling of 14110032410112 in words is "fourteen trillion, one hundred ten billion, thirty-two million, four hundred ten thousand, one hundred twelve".
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