141100403245532 has 12 divisors (see below), whose sum is σ = 247063730122440. Its totient is φ = 70510766067696.

The previous prime is 141100403245523. The next prime is 141100403245583. The reversal of 141100403245532 is 235542304001141.

141100403245532 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a junction number, because it is equal to n+sod(n) for n = 141100403245492 and 141100403245501.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9858880718 + ... + 9858895029.

It is an arithmetic number, because the mean of its divisors is an integer number (20588644176870).

Almost surely, 2^{141100403245532} is an apocalyptic number.

It is an amenable number.

141100403245532 is a deficient number, since it is larger than the sum of its proper divisors (105963326876908).

141100403245532 is a wasteful number, since it uses less digits than its factorization.

141100403245532 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 19717777540 (or 19717777538 counting only the distinct ones).

The product of its (nonzero) digits is 57600, while the sum is 35.

Adding to 141100403245532 its reverse (235542304001141), we get a palindrome (376642707246673).

The spelling of 141100403245532 in words is "one hundred forty-one trillion, one hundred billion, four hundred three million, two hundred forty-five thousand, five hundred thirty-two".