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14110044013103 = 19771624588899
BaseRepresentation
bin1100110101010100000000…
…1010010100001000101111
31211221220111020011000202112
43031111000022110020233
53322134332231404403
650002021552114235
72654263021132103
oct315250012241057
954856436130675
1014110044013103
114550043aa7465
1216ba75523597b
137b47575c11bc
1436ad0342b903
1519707bcdb9d8
hexcd54029422f

14110044013103 has 4 divisors (see below), whose sum is σ = 14181668602200. Its totient is φ = 14038419424008.

The previous prime is 14110044013097. The next prime is 14110044013123. The reversal of 14110044013103 is 30131044001141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14110044013103 - 220 = 14110042964527 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14110044013123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35812294253 + ... + 35812294646.

It is an arithmetic number, because the mean of its divisors is an integer number (3545417150550).

Almost surely, 214110044013103 is an apocalyptic number.

14110044013103 is a deficient number, since it is larger than the sum of its proper divisors (71624589097).

14110044013103 is an equidigital number, since it uses as much as digits as its factorization.

14110044013103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 71624589096.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 14110044013103 its reverse (30131044001141), we get a palindrome (44241088014244).

The spelling of 14110044013103 in words is "fourteen trillion, one hundred ten billion, forty-four million, thirteen thousand, one hundred three".

Divisors: 1 197 71624588899 14110044013103