Base | Representation |
---|---|
bin | 10100100010000110011… |
… | …100111011101100001011 |
3 | 11222220001100211221200011 |
4 | 110202012130323230023 |
5 | 141104214240121210 |
6 | 3000112354052351 |
7 | 203641006435306 |
oct | 24420634735413 |
9 | 4886040757604 |
10 | 1411005004555 |
11 | 4a44495a4083 |
12 | 1a956687a0b7 |
13 | a30988943a3 |
14 | 4c41601db3d |
15 | 26a8438bd8a |
hex | 1488673bb0b |
1411005004555 has 8 divisors (see below), whose sum is σ = 1725153288912. Its totient is φ = 1107505814688.
The previous prime is 1411005004553. The next prime is 1411005004561. The reversal of 1411005004555 is 5554005001141.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1411005004555 - 21 = 1411005004553 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1411005004553) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2662273329 + ... + 2662273858.
It is an arithmetic number, because the mean of its divisors is an integer number (215644161114).
Almost surely, 21411005004555 is an apocalyptic number.
1411005004555 is a deficient number, since it is larger than the sum of its proper divisors (314148284357).
1411005004555 is an equidigital number, since it uses as much as digits as its factorization.
1411005004555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5324547245.
The product of its (nonzero) digits is 10000, while the sum is 31.
The spelling of 1411005004555 in words is "one trillion, four hundred eleven billion, five million, four thousand, five hundred fifty-five".
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