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141100561213 = 197426345327
BaseRepresentation
bin1000001101101000111…
…1111011001100111101
3111111012112121011220121
42003122033323030331
54302433220424323
6144453134414541
713123413660403
oct2033217731475
9444175534817
10141100561213
1154927652067
122341a361451
13103c88ab251
146b87875473
153a0c668a5d
hex20da3fb33d

141100561213 has 4 divisors (see below), whose sum is σ = 148526906560. Its totient is φ = 133674215868.

The previous prime is 141100561211. The next prime is 141100561219. The reversal of 141100561213 is 312165001141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 141100561213 - 21 = 141100561211 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (141100561211) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3713172645 + ... + 3713172682.

It is an arithmetic number, because the mean of its divisors is an integer number (37131726640).

Almost surely, 2141100561213 is an apocalyptic number.

It is an amenable number.

141100561213 is a deficient number, since it is larger than the sum of its proper divisors (7426345347).

141100561213 is an equidigital number, since it uses as much as digits as its factorization.

141100561213 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7426345346.

The product of its (nonzero) digits is 720, while the sum is 25.

Adding to 141100561213 its reverse (312165001141), we get a palindrome (453265562354).

The spelling of 141100561213 in words is "one hundred forty-one billion, one hundred million, five hundred sixty-one thousand, two hundred thirteen".

Divisors: 1 19 7426345327 141100561213