Base | Representation |
---|---|
bin | 1100110101010100110000… |
… | …0001110110010010101101 |
3 | 1211221221000002210201111012 |
4 | 3031111030001312102231 |
5 | 3322140234214322201 |
6 | 50002053423435005 |
7 | 2654300656410416 |
oct | 315251401662255 |
9 | 54857002721435 |
10 | 14110243120301 |
11 | 455013642a669 |
12 | 16ba7aba55a65 |
13 | 7b4789925003 |
14 | 36ad21a5a80d |
15 | 19708e51b5bb |
hex | cd54c0764ad |
14110243120301 has 8 divisors (see below), whose sum is σ = 14133006276480. Its totient is φ = 14087488683168.
The previous prime is 14110243120279. The next prime is 14110243120361. The reversal of 14110243120301 is 10302134201141.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 14110243120301 - 210 = 14110243119277 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14110243120361) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1063385 + ... + 5417681.
It is an arithmetic number, because the mean of its divisors is an integer number (1766625784560).
Almost surely, 214110243120301 is an apocalyptic number.
It is an amenable number.
14110243120301 is a deficient number, since it is larger than the sum of its proper divisors (22763156179).
14110243120301 is an equidigital number, since it uses as much as digits as its factorization.
14110243120301 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4359523.
The product of its (nonzero) digits is 576, while the sum is 23.
Adding to 14110243120301 its reverse (10302134201141), we get a palindrome (24412377321442).
The spelling of 14110243120301 in words is "fourteen trillion, one hundred ten billion, two hundred forty-three million, one hundred twenty thousand, three hundred one".
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