Base | Representation |
---|---|
bin | 10100100010000111100… |
… | …111000000000010011111 |
3 | 11222220002201101102001121 |
4 | 110202013213000002133 |
5 | 141104234222433043 |
6 | 3000114330151411 |
7 | 203641333454140 |
oct | 24420747000237 |
9 | 4886081342047 |
10 | 1411024421023 |
11 | 4a4459555a48 |
12 | 1a9571282567 |
13 | a309c902019 |
14 | 4c418835ac7 |
15 | 26a85e24ded |
hex | 148879c009f |
1411024421023 has 4 divisors (see below), whose sum is σ = 1612599338320. Its totient is φ = 1209449503728.
The previous prime is 1411024421011. The next prime is 1411024421083. The reversal of 1411024421023 is 3201244201141.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1411024421023 - 217 = 1411024289951 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1411024421003) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 100787458638 + ... + 100787458651.
It is an arithmetic number, because the mean of its divisors is an integer number (403149834580).
Almost surely, 21411024421023 is an apocalyptic number.
1411024421023 is a deficient number, since it is larger than the sum of its proper divisors (201574917297).
1411024421023 is an equidigital number, since it uses as much as digits as its factorization.
1411024421023 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 201574917296.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 1411024421023 its reverse (3201244201141), we get a palindrome (4612268622164).
The spelling of 1411024421023 in words is "one trillion, four hundred eleven billion, twenty-four million, four hundred twenty-one thousand, twenty-three".
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