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14110317520421 is a prime number
BaseRepresentation
bin1100110101010101000001…
…1101101010011000100101
31211221221012021210122021012
43031111100131222120211
53322140412241123141
650002105042232005
72654302551661403
oct315252035523045
954857167718235
1014110317520421
114550174426571
1216ba810955605
137b479c174555
1436ad2b8a6473
15197095d15ceb
hexcd55076a625

14110317520421 has 2 divisors, whose sum is σ = 14110317520422. Its totient is φ = 14110317520420.

The previous prime is 14110317520391. The next prime is 14110317520423. The reversal of 14110317520421 is 12402571301141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7598705730625 + 6511611789796 = 2756575^2 + 2551786^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14110317520421 is a prime.

Together with 14110317520423, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14110317520423) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7055158760210 + 7055158760211.

It is an arithmetic number, because the mean of its divisors is an integer number (7055158760211).

Almost surely, 214110317520421 is an apocalyptic number.

It is an amenable number.

14110317520421 is a deficient number, since it is larger than the sum of its proper divisors (1).

14110317520421 is an equidigital number, since it uses as much as digits as its factorization.

14110317520421 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6720, while the sum is 32.

Adding to 14110317520421 its reverse (12402571301141), we get a palindrome (26512888821562).

The spelling of 14110317520421 in words is "fourteen trillion, one hundred ten billion, three hundred seventeen million, five hundred twenty thousand, four hundred twenty-one".