Base | Representation |
---|---|
bin | 1000001101101001110… |
… | …1000011110000100100 |
3 | 111111012210002002201010 |
4 | 2003122131003300210 |
5 | 4302440111113012 |
6 | 144453340302220 |
7 | 13123455150150 |
oct | 2033235036044 |
9 | 444183062633 |
10 | 141104004132 |
11 | 54929593853 |
12 | 2341b541970 |
13 | 103c9515390 |
14 | 6b880d0060 |
15 | 3a0cae8c3c |
hex | 20da743c24 |
141104004132 has 96 divisors (see below), whose sum is σ = 408939731200. Its totient is φ = 36872796672.
The previous prime is 141104004109. The next prime is 141104004143. The reversal of 141104004132 is 231400401141.
It is a super-5 number, since 5×1411040041325 (a number of 57 digits) contains 55555 as substring.
It is a Harshad number since it is a multiple of its sum of digits (21).
It is a junction number, because it is equal to n+sod(n) for n = 141104004099 and 141104004108.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 473707 + ... + 711762.
Almost surely, 2141104004132 is an apocalyptic number.
141104004132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
141104004132 is an abundant number, since it is smaller than the sum of its proper divisors (267835727068).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
141104004132 is a wasteful number, since it uses less digits than its factorization.
141104004132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1185605 (or 1185603 counting only the distinct ones).
The product of its (nonzero) digits is 384, while the sum is 21.
Adding to 141104004132 its reverse (231400401141), we get a palindrome (372504405273).
The spelling of 141104004132 in words is "one hundred forty-one billion, one hundred four million, four thousand, one hundred thirty-two".
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