14111031133 has 4 divisors (see below), whose sum is σ = 14113673568. Its totient is φ = 14108388700.

The previous prime is 14111031127. The next prime is 14111031157. The reversal of 14111031133 is 33113011141.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33113011141 = 7 ⋅4730430163.

It is a cyclic number.

It is not a de Polignac number, because 14111031133 - 2¹⁷ = 14110900061 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 14111031133.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14111031173) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1313191 + ... + 1323892.

It is an arithmetic number, because the mean of its divisors is an integer number (3528418392).

Almost surely, 2^14111031133 is an apocalyptic number.

It is an amenable number.

14111031133 is a deficient number, since it is larger than the sum of its proper divisors (2642435).

14111031133 is an equidigital number, since it uses as much as digits as its factorization.

14111031133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2642434.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 14111031133 its reverse (33113011141), we get a palindrome (47224042274).

The spelling of 14111031133 in words is "fourteen billion, one hundred eleven million, thirty-one thousand, one hundred thirty-three".