14111103435133 has 4 divisors (see below), whose sum is σ = 14941168343100. Its totient is φ = 13281038527168.

The previous prime is 14111103435113. The next prime is 14111103435173. The reversal of 14111103435133 is 33153430111141.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 11410330014724 + 2700773420409 = 3377918^2 + 1643403^2 .

It is a cyclic number.

It is not a de Polignac number, because 14111103435133 - 2⁹ = 14111103434621 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14111103435095 and 14111103435104.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14111103435113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 415032453958 + ... + 415032453991.

It is an arithmetic number, because the mean of its divisors is an integer number (3735292085775).

Almost surely, 2^{14111103435133} is an apocalyptic number.

It is an amenable number.

14111103435133 is a deficient number, since it is larger than the sum of its proper divisors (830064907967).

14111103435133 is an equidigital number, since it uses as much as digits as its factorization.

14111103435133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 830064907966.

The product of its (nonzero) digits is 6480, while the sum is 31.

Adding to 14111103435133 its reverse (33153430111141), we get a palindrome (47264533546274).

The spelling of 14111103435133 in words is "fourteen trillion, one hundred eleven billion, one hundred three million, four hundred thirty-five thousand, one hundred thirty-three".