14111244031 has 2 divisors, whose sum is σ = 14111244032. Its totient is φ = 14111244030.

The previous prime is 14111244029. The next prime is 14111244047. The reversal of 14111244031 is 13044211141.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 14111244031 - 2¹ = 14111244029 is a prime.

It is a super-2 number, since 2×14111244031² (a number of 21 digits) contains 22 as substring.

Together with 14111244029, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 14111243993 and 14111244011.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14111241031) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7055622015 + 7055622016.

It is an arithmetic number, because the mean of its divisors is an integer number (7055622016).

Almost surely, 2^14111244031 is an apocalyptic number.

14111244031 is a deficient number, since it is larger than the sum of its proper divisors (1).

14111244031 is an equidigital number, since it uses as much as digits as its factorization.

14111244031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 384, while the sum is 22.

Adding to 14111244031 its reverse (13044211141), we get a palindrome (27155455172).

The spelling of 14111244031 in words is "fourteen billion, one hundred eleven million, two hundred forty-four thousand, thirty-one".