14111324030221 has 4 divisors (see below), whose sum is σ = 15394171669344. Its totient is φ = 12828476391100.

The previous prime is 14111324030197. The next prime is 14111324030239. The reversal of 14111324030221 is 12203042311141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14111324030221 - 2⁵ = 14111324030189 is a prime.

It is a super-2 number, since 2×14111324030221² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14111324030281) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 641423819545 + ... + 641423819566.

It is an arithmetic number, because the mean of its divisors is an integer number (3848542917336).

Almost surely, 2^{14111324030221} is an apocalyptic number.

14111324030221 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

14111324030221 is a deficient number, since it is larger than the sum of its proper divisors (1282847639123).

14111324030221 is a wasteful number, since it uses less digits than its factorization.

14111324030221 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1282847639122.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 14111324030221 its reverse (12203042311141), we get a palindrome (26314366341362).

The spelling of 14111324030221 in words is "fourteen trillion, one hundred eleven billion, three hundred twenty-four million, thirty thousand, two hundred twenty-one".