Base | Representation |
---|---|
bin | 11010010010001101… |
… | …01110001010010111 |
3 | 1100102110002102110122 |
4 | 31021012232022113 |
5 | 212400004304344 |
6 | 10252132142155 |
7 | 1006456632422 |
oct | 151106561227 |
9 | 40373072418 |
10 | 14111400599 |
11 | 5a9157714a |
12 | 2899a6795b |
13 | 143b7148aa |
14 | 97c1d49b9 |
15 | 578cdaaee |
hex | 3491ae297 |
14111400599 has 2 divisors, whose sum is σ = 14111400600. Its totient is φ = 14111400598.
The previous prime is 14111400593. The next prime is 14111400683. The reversal of 14111400599 is 99500411141.
14111400599 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14111400599 - 212 = 14111396503 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14111400593) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7055700299 + 7055700300.
It is an arithmetic number, because the mean of its divisors is an integer number (7055700300).
Almost surely, 214111400599 is an apocalyptic number.
14111400599 is a deficient number, since it is larger than the sum of its proper divisors (1).
14111400599 is an equidigital number, since it uses as much as digits as its factorization.
14111400599 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6480, while the sum is 35.
The spelling of 14111400599 in words is "fourteen billion, one hundred eleven million, four hundred thousand, five hundred ninety-nine".
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