Base | Representation |
---|---|
bin | 11010010010001101… |
… | …10000111100011110 |
3 | 1100102110010000002211 |
4 | 31021012300330132 |
5 | 212400010140443 |
6 | 10252132311034 |
7 | 1006460010565 |
oct | 151106607436 |
9 | 40373100084 |
10 | 14111411998 |
11 | 5a91584772 |
12 | 2899a7247a |
13 | 143b719b38 |
14 | 97c1d8bdc |
15 | 578cde19d |
hex | 3491b0f1e |
14111411998 has 4 divisors (see below), whose sum is σ = 21167118000. Its totient is φ = 7055705998.
The previous prime is 14111411989. The next prime is 14111412011. The reversal of 14111411998 is 89911411141.
14111411998 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 89911411141 = 76303 ⋅1178347.
It is a self number, because there is not a number n which added to its sum of digits gives 14111411998.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3527852998 + ... + 3527853001.
It is an arithmetic number, because the mean of its divisors is an integer number (5291779500).
Almost surely, 214111411998 is an apocalyptic number.
14111411998 is a deficient number, since it is larger than the sum of its proper divisors (7055706002).
14111411998 is an equidigital number, since it uses as much as digits as its factorization.
14111411998 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7055706001.
The product of its digits is 10368, while the sum is 40.
The spelling of 14111411998 in words is "fourteen billion, one hundred eleven million, four hundred eleven thousand, nine hundred ninety-eight".
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