14111412101 has 4 divisors (see below), whose sum is σ = 14161276032. Its totient is φ = 14061548172.

The previous prime is 14111412083. The next prime is 14111412113. The reversal of 14111412101 is 10121411141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 10121411141 = 647 ⋅15643603.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14111412101 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 14111412101.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14111412191) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24931541 + ... + 24932106.

It is an arithmetic number, because the mean of its divisors is an integer number (3540319008).

Almost surely, 2^14111412101 is an apocalyptic number.

It is an amenable number.

14111412101 is a deficient number, since it is larger than the sum of its proper divisors (49863931).

14111412101 is an equidigital number, since it uses as much as digits as its factorization.

14111412101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 49863930.

The product of its (nonzero) digits is 32, while the sum is 17.

Adding to 14111412101 its reverse (10121411141), we get a palindrome (24232823242).

The spelling of 14111412101 in words is "fourteen billion, one hundred eleven million, four hundred twelve thousand, one hundred one".