Search a number
-
+
14111424547 = 111282856777
BaseRepresentation
bin11010010010001101…
…10100000000100011
31100102110010122022121
431021012310000203
5212400011041142
610252132445111
71006460062303
oct151106640043
940373118277
1014111424547
115a91593140
122899a79797
13143b72276c
1497c1dd603
15578ce2c67
hex3491b4023

14111424547 has 4 divisors (see below), whose sum is σ = 15394281336. Its totient is φ = 12828567760.

The previous prime is 14111424539. The next prime is 14111424557. The reversal of 14111424547 is 74542411141.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 74542411141 = 116776582831.

It is a cyclic number.

It is not a de Polignac number, because 14111424547 - 23 = 14111424539 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14111424517) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 641428378 + ... + 641428399.

It is an arithmetic number, because the mean of its divisors is an integer number (3848570334).

Almost surely, 214111424547 is an apocalyptic number.

14111424547 is a deficient number, since it is larger than the sum of its proper divisors (1282856789).

14111424547 is a wasteful number, since it uses less digits than its factorization.

14111424547 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1282856788.

The product of its digits is 17920, while the sum is 34.

Adding to 14111424547 its reverse (74542411141), we get a palindrome (88653835688).

The spelling of 14111424547 in words is "fourteen billion, one hundred eleven million, four hundred twenty-four thousand, five hundred forty-seven".

Divisors: 1 11 1282856777 14111424547