1411144002131 has 2 divisors, whose sum is σ = 1411144002132. Its totient is φ = 1411144002130.

The previous prime is 1411144002077. The next prime is 1411144002133. The reversal of 1411144002131 is 1312004411141.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1411144002131 - 2¹⁴ = 1411143985747 is a prime.

It is a super-2 number, since 2×1411144002131² (a number of 25 digits) contains 22 as substring.

Together with 1411144002133, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1411144002097 and 1411144002106.

It is not a weakly prime, because it can be changed into another prime (1411144002133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 705572001065 + 705572001066.

It is an arithmetic number, because the mean of its divisors is an integer number (705572001066).

Almost surely, 2^{1411144002131} is an apocalyptic number.

1411144002131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1411144002131 is an equidigital number, since it uses as much as digits as its factorization.

1411144002131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 384, while the sum is 23.

Adding to 1411144002131 its reverse (1312004411141), we get a palindrome (2723148413272).

The spelling of 1411144002131 in words is "one trillion, four hundred eleven billion, one hundred forty-four million, two thousand, one hundred thirty-one".