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14111515024141 is a prime number
BaseRepresentation
bin1100110101011001011111…
…0101110001101100001101
31211222001021202010010112211
43031112113311301230031
53322200340321233031
650002423541030421
72654344332412033
oct315262765615415
954861252103484
1014111515024141
114550729387867
1216baaa59b5411
137b49302a3732
1436b002946553
1519711600bbb1
hexcd597d71b0d

14111515024141 has 2 divisors, whose sum is σ = 14111515024142. Its totient is φ = 14111515024140.

The previous prime is 14111515024099. The next prime is 14111515024151. The reversal of 14111515024141 is 14142051511141.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 14069655910116 + 41859114025 = 3750954^2 + 204595^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14111515024141 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14111515024151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7055757512070 + 7055757512071.

It is an arithmetic number, because the mean of its divisors is an integer number (7055757512071).

Almost surely, 214111515024141 is an apocalyptic number.

It is an amenable number.

14111515024141 is a deficient number, since it is larger than the sum of its proper divisors (1).

14111515024141 is an equidigital number, since it uses as much as digits as its factorization.

14111515024141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3200, while the sum is 31.

Adding to 14111515024141 its reverse (14142051511141), we get a palindrome (28253566535282).

The spelling of 14111515024141 in words is "fourteen trillion, one hundred eleven billion, five hundred fifteen million, twenty-four thousand, one hundred forty-one".