Base | Representation |
---|---|
bin | 1100110101011001011111… |
… | …0110111010100001000010 |
3 | 1211222001021202200021201201 |
4 | 3031112113312322201002 |
5 | 3322200340410304214 |
6 | 50002423551251414 |
7 | 2654344335063505 |
oct | 315262766724102 |
9 | 54861252607651 |
10 | 14111515322434 |
11 | 4550729570992 |
12 | 16baaa5b19b6a |
13 | 7b493037943a |
14 | 36b0029c313c |
15 | 19711606a274 |
hex | cd597dba842 |
14111515322434 has 4 divisors (see below), whose sum is σ = 21167272983654. Its totient is φ = 7055757661216.
The previous prime is 14111515322369. The next prime is 14111515322461. The reversal of 14111515322434 is 43422351511141.
It is a happy number.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 11182984745409 + 2928530577025 = 3344097^2 + 1711295^2 .
It is a junction number, because it is equal to n+sod(n) for n = 14111515322393 and 14111515322402.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3527878830607 + ... + 3527878830610.
Almost surely, 214111515322434 is an apocalyptic number.
14111515322434 is a deficient number, since it is larger than the sum of its proper divisors (7055757661220).
14111515322434 is an equidigital number, since it uses as much as digits as its factorization.
14111515322434 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7055757661219.
The product of its digits is 57600, while the sum is 37.
Adding to 14111515322434 its reverse (43422351511141), we get a palindrome (57533866833575).
The spelling of 14111515322434 in words is "fourteen trillion, one hundred eleven billion, five hundred fifteen million, three hundred twenty-two thousand, four hundred thirty-four".
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