14111553000253 has 4 divisors (see below), whose sum is σ = 14131179639360. Its totient is φ = 14091926361148.

The previous prime is 14111553000221. The next prime is 14111553000287. The reversal of 14111553000253 is 35200035511141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14111553000253 - 2⁵ = 14111553000221 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14111553000553) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9813318475 + ... + 9813319912.

It is an arithmetic number, because the mean of its divisors is an integer number (3532794909840).

Almost surely, 2^{14111553000253} is an apocalyptic number.

It is an amenable number.

14111553000253 is a deficient number, since it is larger than the sum of its proper divisors (19626639107).

14111553000253 is an equidigital number, since it uses as much as digits as its factorization.

14111553000253 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 19626639106.

The product of its (nonzero) digits is 9000, while the sum is 31.

Adding to 14111553000253 its reverse (35200035511141), we get a palindrome (49311588511394).

The spelling of 14111553000253 in words is "fourteen trillion, one hundred eleven billion, five hundred fifty-three million, two hundred fifty-three", and thus it is an aban number.