Base | Representation |
---|---|
bin | 100000000101100010000010… |
… | …111101011100100111101110 |
3 | 200111122201022011000102220211 |
4 | 200011202002331130213232 |
5 | 121444032413002422340 |
6 | 1220044314451133034 |
7 | 41503261510606462 |
oct | 4005420275344756 |
9 | 614581264012824 |
10 | 141117642623470 |
11 | 40a67724371397 |
12 | 139b1664ba417a |
13 | 609844b67c636 |
14 | 26bc1b79544a2 |
15 | 114abd8ca15ea |
hex | 805882f5c9ee |
141117642623470 has 16 divisors (see below), whose sum is σ = 255288197714400. Its totient is φ = 56163403495584.
The previous prime is 141117642623431. The next prime is 141117642623473. The reversal of 141117642623470 is 74326246711141.
It is a happy number.
141117642623470 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (141117642623473) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 35456692137 + ... + 35456696116.
It is an arithmetic number, because the mean of its divisors is an integer number (15955512357150).
Almost surely, 2141117642623470 is an apocalyptic number.
141117642623470 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
141117642623470 is a deficient number, since it is larger than the sum of its proper divisors (114170555090930).
141117642623470 is a wasteful number, since it uses less digits than its factorization.
141117642623470 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 70913388459.
The product of its (nonzero) digits is 1354752, while the sum is 49.
The spelling of 141117642623470 in words is "one hundred forty-one trillion, one hundred seventeen billion, six hundred forty-two million, six hundred twenty-three thousand, four hundred seventy".
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