14112000001 has 4 divisors (see below), whose sum is σ = 15394909104. Its totient is φ = 12829090900.

The previous prime is 14111999987. The next prime is 14112000011. The reversal of 14112000001 is 10000021141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 10000021141 = 11 ⋅909092831.

It is a cyclic number.

It is not a de Polignac number, because 14112000001 - 2⁷ = 14111999873 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14112000011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 641454535 + ... + 641454556.

It is an arithmetic number, because the mean of its divisors is an integer number (3848727276).

Almost surely, 2^14112000001 is an apocalyptic number.

14112000001 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

14112000001 is a deficient number, since it is larger than the sum of its proper divisors (1282909103).

14112000001 is a wasteful number, since it uses less digits than its factorization.

14112000001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1282909102.

The product of its (nonzero) digits is 8, while the sum is 10.

Adding to 14112000001 its reverse (10000021141), we get a palindrome (24112021142).

The spelling of 14112000001 in words is "fourteen billion, one hundred twelve million, one", and thus it is an aban number.