14112024135301 has 2 divisors, whose sum is σ = 14112024135302. Its totient is φ = 14112024135300.

The previous prime is 14112024135289. The next prime is 14112024135323. The reversal of 14112024135301 is 10353142021141.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10463736952900 + 3648287182401 = 3234770^2 + 1910049^2 .

It is a cyclic number.

It is not a de Polignac number, because 14112024135301 - 2³¹ = 14109876651653 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 14112024135301.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14112024132301) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7056012067650 + 7056012067651.

It is an arithmetic number, because the mean of its divisors is an integer number (7056012067651).

Almost surely, 2^{14112024135301} is an apocalyptic number.

It is an amenable number.

14112024135301 is a deficient number, since it is larger than the sum of its proper divisors (1).

14112024135301 is an equidigital number, since it uses as much as digits as its factorization.

14112024135301 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2880, while the sum is 28.

Adding to 14112024135301 its reverse (10353142021141), we get a palindrome (24465166156442).

The spelling of 14112024135301 in words is "fourteen trillion, one hundred twelve billion, twenty-four million, one hundred thirty-five thousand, three hundred one".