Base | Representation |
---|---|
bin | 1100110101011011011010… |
… | …0011000110001101100011 |
3 | 1211222002121122112211222201 |
4 | 3031112312203012031203 |
5 | 3322202414214034110 |
6 | 50002551023314031 |
7 | 2654363156462116 |
oct | 315266643061543 |
9 | 54862548484881 |
10 | 14112030221155 |
11 | 4550973183a19 |
12 | 16bb00a44b917 |
13 | 7b49b2c49a39 |
14 | 36b05113657d |
15 | 197146377b3a |
hex | cd5b68c6363 |
14112030221155 has 8 divisors (see below), whose sum is σ = 16945733430000. Its totient is φ = 11282092733856.
The previous prime is 14112030221153. The next prime is 14112030221287. The reversal of 14112030221155 is 55112203021141.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 14112030221155 - 21 = 14112030221153 is a prime.
It is not an unprimeable number, because it can be changed into a prime (14112030221153) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 941422140 + ... + 941437129.
It is an arithmetic number, because the mean of its divisors is an integer number (2118216678750).
Almost surely, 214112030221155 is an apocalyptic number.
14112030221155 is a deficient number, since it is larger than the sum of its proper divisors (2833703208845).
14112030221155 is a wasteful number, since it uses less digits than its factorization.
14112030221155 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1882860773.
The product of its (nonzero) digits is 2400, while the sum is 28.
Adding to 14112030221155 its reverse (55112203021141), we get a palindrome (69224233242296).
The spelling of 14112030221155 in words is "fourteen trillion, one hundred twelve billion, thirty million, two hundred twenty-one thousand, one hundred fifty-five".
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