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14112030221155 = 514991882859269
BaseRepresentation
bin1100110101011011011010…
…0011000110001101100011
31211222002121122112211222201
43031112312203012031203
53322202414214034110
650002551023314031
72654363156462116
oct315266643061543
954862548484881
1014112030221155
114550973183a19
1216bb00a44b917
137b49b2c49a39
1436b05113657d
15197146377b3a
hexcd5b68c6363

14112030221155 has 8 divisors (see below), whose sum is σ = 16945733430000. Its totient is φ = 11282092733856.

The previous prime is 14112030221153. The next prime is 14112030221287. The reversal of 14112030221155 is 55112203021141.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 14112030221155 - 21 = 14112030221153 is a prime.

It is not an unprimeable number, because it can be changed into a prime (14112030221153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 941422140 + ... + 941437129.

It is an arithmetic number, because the mean of its divisors is an integer number (2118216678750).

Almost surely, 214112030221155 is an apocalyptic number.

14112030221155 is a deficient number, since it is larger than the sum of its proper divisors (2833703208845).

14112030221155 is a wasteful number, since it uses less digits than its factorization.

14112030221155 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1882860773.

The product of its (nonzero) digits is 2400, while the sum is 28.

Adding to 14112030221155 its reverse (55112203021141), we get a palindrome (69224233242296).

The spelling of 14112030221155 in words is "fourteen trillion, one hundred twelve billion, thirty million, two hundred twenty-one thousand, one hundred fifty-five".

Divisors: 1 5 1499 7495 1882859269 9414296345 2822406044231 14112030221155