Base | Representation |
---|---|
bin | 10100100010010010011… |
… | …001000001011010100111 |
3 | 11222220120022202022122001 |
4 | 110202102121001122213 |
5 | 141110122024243043 |
6 | 3000144311150131 |
7 | 203645661116512 |
oct | 24422231013247 |
9 | 4886508668561 |
10 | 1411205306023 |
11 | 4a4541672587 |
12 | 1a9601975347 |
13 | a30cb225976 |
14 | 4c43487dd79 |
15 | 26a96c5574d |
hex | 148926416a7 |
1411205306023 has 4 divisors (see below), whose sum is σ = 1441230950880. Its totient is φ = 1381179661168.
The previous prime is 1411205305997. The next prime is 1411205306029. The reversal of 1411205306023 is 3206035021141.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1411205306023 - 29 = 1411205305511 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1411205305982 and 1411205306000.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1411205306029) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15012822358 + ... + 15012822451.
It is an arithmetic number, because the mean of its divisors is an integer number (360307737720).
Almost surely, 21411205306023 is an apocalyptic number.
1411205306023 is a deficient number, since it is larger than the sum of its proper divisors (30025644857).
1411205306023 is an equidigital number, since it uses as much as digits as its factorization.
1411205306023 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 30025644856.
The product of its (nonzero) digits is 4320, while the sum is 28.
The spelling of 1411205306023 in words is "one trillion, four hundred eleven billion, two hundred five million, three hundred six thousand, twenty-three".
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