141121114234343 has 8 divisors (see below), whose sum is σ = 141408020208000. Its totient is φ = 140834224654200.

The previous prime is 141121114234337. The next prime is 141121114234363. The reversal of 141121114234343 is 343432411121141.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 141121114234343 - 2⁶ = 141121114234279 is a prime.

It is a super-2 number, since 2×141121114234343² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (141121114234363) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 13210046 + ... + 21371652.

It is an arithmetic number, because the mean of its divisors is an integer number (17676002526000).

Almost surely, 2^{141121114234343} is an apocalyptic number.

141121114234343 is a deficient number, since it is larger than the sum of its proper divisors (286905973657).

141121114234343 is an equidigital number, since it uses as much as digits as its factorization.

141121114234343 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8196757.

The product of its digits is 27648, while the sum is 35.

Adding to 141121114234343 its reverse (343432411121141), we get a palindrome (484553525355484).

The spelling of 141121114234343 in words is "one hundred forty-one trillion, one hundred twenty-one billion, one hundred fourteen million, two hundred thirty-four thousand, three hundred forty-three".