141121131132 has 24 divisors (see below), whose sum is σ = 332360050176. Its totient is φ = 46600746928.

The previous prime is 141121131101. The next prime is 141121131139. The reversal of 141121131132 is 231131121141.

It is a happy number.

It is a nude number because it is divisible by every one of its digits.

It is a junction number, because it is equal to n+sod(n) for n = 141121131099 and 141121131108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (141121131139) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 54952428 + ... + 54954995.

It is an arithmetic number, because the mean of its divisors is an integer number (13848335424).

Almost surely, 2^141121131132 is an apocalyptic number.

141121131132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

141121131132 is an abundant number, since it is smaller than the sum of its proper divisors (191238919044).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

141121131132 is a wasteful number, since it uses less digits than its factorization.

141121131132 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 109907537 (or 109907535 counting only the distinct ones).

The product of its digits is 144, while the sum is 21.

Adding to 141121131132 its reverse (231131121141), we get a palindrome (372252252273).

Subtracting 141121131132 from its reverse (231131121141), we obtain a palindrome (90009990009).

The spelling of 141121131132 in words is "one hundred forty-one billion, one hundred twenty-one million, one hundred thirty-one thousand, one hundred thirty-two".