141122121410033 has 2 divisors, whose sum is σ = 141122121410034. Its totient is φ = 141122121410032.

The previous prime is 141122121410003. The next prime is 141122121410087. The reversal of 141122121410033 is 330014121221141.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 105774066761104 + 35348054648929 = 10284652^2 + 5945423^2 .

It is a cyclic number.

It is not a de Polignac number, because 141122121410033 - 2³² = 141117826442737 is a prime.

It is a super-2 number, since 2×141122121410033² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 141122121409984 and 141122121410011.

It is not a weakly prime, because it can be changed into another prime (141122121410003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70561060705016 + 70561060705017.

It is an arithmetic number, because the mean of its divisors is an integer number (70561060705017).

Almost surely, 2^{141122121410033} is an apocalyptic number.

It is an amenable number.

141122121410033 is a deficient number, since it is larger than the sum of its proper divisors (1).

141122121410033 is an equidigital number, since it uses as much as digits as its factorization.

141122121410033 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 26.

Adding to 141122121410033 its reverse (330014121221141), we get a palindrome (471136242631174).

The spelling of 141122121410033 in words is "one hundred forty-one trillion, one hundred twenty-two billion, one hundred twenty-one million, four hundred ten thousand, thirty-three".