141123343321141 has 4 divisors (see below), whose sum is σ = 142578223149292. Its totient is φ = 139668463492992.

The previous prime is 141123343321133. The next prime is 141123343321189.

141123343321141 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 50320168256241 + 90803175064900 = 7093671^2 + 9529070^2 .

It is a cyclic number.

It is not a de Polignac number, because 141123343321141 - 2³ = 141123343321133 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 141123343321097 and 141123343321106.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (141123343331141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 727439913930 + ... + 727439914123.

It is an arithmetic number, because the mean of its divisors is an integer number (35644555787323).

Almost surely, 2^{141123343321141} is an apocalyptic number.

It is an amenable number.

141123343321141 is a deficient number, since it is larger than the sum of its proper divisors (1454879828151).

141123343321141 is an equidigital number, since it uses as much as digits as its factorization.

141123343321141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1454879828150.

The product of its digits is 20736, while the sum is 34.

The spelling of 141123343321141 in words is "one hundred forty-one trillion, one hundred twenty-three billion, three hundred forty-three million, three hundred twenty-one thousand, one hundred forty-one".