141124000433 has 6 divisors (see below), whose sum is σ = 152814746214. Its totient is φ = 130268307936.

The previous prime is 141124000421. The next prime is 141124000469. The reversal of 141124000433 is 334000421141.

141124000433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in 3 ways, for example, as 17179869184 + 123944131249 = 131072^2 + 352057^2 .

It is not a de Polignac number, because 141124000433 - 2¹⁴ = 141123984049 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 141124000399 and 141124000408.

It is not an unprimeable number, because it can be changed into a prime (141124000333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 417526460 + ... + 417526797.

It is an arithmetic number, because the mean of its divisors is an integer number (25469124369).

Almost surely, 2^141124000433 is an apocalyptic number.

141124000433 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

141124000433 is a deficient number, since it is larger than the sum of its proper divisors (11690745781).

141124000433 is an equidigital number, since it uses as much as digits as its factorization.

141124000433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 835053283 (or 835053270 counting only the distinct ones).

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 141124000433 its reverse (334000421141), we get a palindrome (475124421574).

The spelling of 141124000433 in words is "one hundred forty-one billion, one hundred twenty-four million, four hundred thirty-three", and thus it is an aban number.